0=x^2+10x-144

Solution for 0=x^2+10x-144 equation:

0=x^2+10x-144

We move all terms to the left:

0-(x^2+10x-144)=0

We add all the numbers together, and all the variables

-(x^2+10x-144)=0

We get rid of parentheses

-x^2-10x+144=0

We add all the numbers together, and all the variables

-1x^2-10x+144=0

a = -1; b = -10; c = +144;
Δ = b2-4ac
Δ = -102-4·(-1)·144
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-26}{2*-1}=\frac{-16}{-2}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+26}{2*-1}=\frac{36}{-2}
=-18
$